How do you factor $2 x^{2} + 4 x - 6$ $2x^{2}+4x-6$ ?

Question

How do you factor $2 x^{2} + 4 x - 6$ $2x^{2}+4x-6$ ?

2 Answers

Impact of this question

4154 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-11T09:46:51

You cannot (unless you use imaginary numbers, i.e. i).
Maybe check that there is no typo.

Explanation:

The Quadratic Formula: For $a x^{2} + b x + c = 0$ $ax^2" + bx + c = 0$ , the values of x (factors) which are the solutions of the equation are given by:
$x = \frac{b \pm \sqrt{4 \cdot a \cdot c}}{2 \cdot a}$ $x=(b+-sqrt(4*a*c))/(2*a)$

Here, a=2, b=4 and c=-6, so

$x = \frac{4 \pm \sqrt{4 \cdot 2 \cdot (- 6)}}{2 \cdot 2}$ $x=(4+-sqrt(4*2*(-6)))/(2*2)$

$x = (4 \pm \frac{\sqrt{- 48}}{4})$ $x=(4+-sqrt(-48)/4)$

since you cannot take the square root of a negative number (-48), there are no real factors of teh equation. this means that, when plotted on a graph, the X-axis is never crossed.

Answer 2 · 2018-06-11T10:00:49

$2 (x + 3) (x - 1)$ $2(x+3)(x-1)$

Explanation:

$take out a common factor 2$ $"take out a "color(blue)"common factor "2$

$= 2 (x^{2} + 2 x - 3)$ $=2(x^2+2x-3)$

$the factors of - 3 which sum to + 2 are + 3 and - 1$ $"the factors of - 3 which sum to + 2 are + 3 and - 1"$

$= 2 (x + 3) (x - 1)$ $=2(x+3)(x-1)$

Science

Math

Humanities

... and beyond

How do you factor $2 x^{2} + 4 x - 6$ $2x^{2}+4x-6$ ?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you factor 2x2+4x−62x^{2}+4x-6?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question

How do you factor $2 x^{2} + 4 x - 6$ $2x^{2}+4x-6$ ?