Question

Please help find the coordinates for the following parabola ?

Answer 1

See below

Explanation:

We know that generic parabola has vertex in `x=-b/(2a)`

Where `ax^2+bx+c=f(x)`

In our case `-b/(2a)=-16/8=-2`

The value in this point is `f(-2)=4·(-2)^2+16·(-2)+8=-8`

The vertex is at the point `(-2,-8)`

Here you are a graphic of this problem