How do you write #7 – 3(x – y) = 5x + 2# in standard form?

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Answer 1 · 2018-06-11T13:38:05

#8x - 3y = 5# is the standard form of equation.

#7 - 3(x-y) = 5x + 2#

Standard form of linear equation is #Ax + By = C#

#7 - 3x + 3y = 5x + 2#

#5x + 3x - 3y = 7 - 2#

#8x - 3y = 5# is the standard form of equation.

Answer 2 · 2018-06-11T13:40:19

#3y-8x=-5#

Standard form will be #ax+by=c# or #by+ax=c#
Hence simplify the given equation first.

#7-3(x-y)=5x+2#

Open the brackets:

#7-3x+3y=5x+2#

Subtract #7# both sides:

#7-7-3x+3y=5x+2-7#

#-3x+3y=5x-5#

Subtract #5x# both sides:

#-3x-5x+3y=5x-5x-5#

#-8x+3y=-5#

Re-arranging and we get:

#3y-8x=-5#

Hope this helps!