6x-9/x-5?

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6x-9/x-5?

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Answer 1 · 2018-06-11T14:06:56

$x 1 = - 0.88$ $x1= -0.88$

$x 2 = 1.71$ $x2=1.71$

Explanation:

Starting with $6 x - \frac{9}{x} - 5 = 0$ $6x-9/x-5=0$ ,
multiplying both sides of the equation with $x$ $x$ , and reordering the terms gives the equation to solve as:

$6 x^{2} - 5 x - 9 = 0$ $6x^2-5x-9=0$

factoring (with $a = 6, b = - 5, c = - 9$ $a=6, b=-5, c=-9$ ) gives the following solutions for x:

$x = \frac{5 \pm \sqrt{{(- 5)}^{2} - 4 \times 6 \times (- 9)}}{2 \times 6}$ $x= (5+-sqrt((-5)^2-4xx6xx(-9)))/(2xx6)$

$x 1 = - 0.88$ $x1= -0.88$

$x 2 = 1.71$ $x2=1.71$

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6x-9/x-5?

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