How do you factor # 14x^2+23xy+3y^2#?
1 Answer
Jun 11, 2018
Explanation:
#"although the quadratic has 2 variables we deal with it"#
#"in the same manner as one variable quadratics"#
#"using the a-c method to factor"#
#"the factors of the product "14xx3=42#
#"which sum to + 23 are + 21 and + 2"#
#"split the middle term using these factors"#
#14x^2+21xy+2xy+3y^2larrcolor(blue)"factor by grouping"#
#=color(red)(7x)(2x+3y)color(red)(+y)(2x+3y)#
#"take out the "color(blue)"common factor "(2x+3y)#
#=(2x+3y)(color(red)(7x+y))#
#14x^2+23xy+3y^2=(2x+3y)(7x+y)#
