An object with a mass of #7 kg# is hanging from a spring with a constant of #2 (kg)/s^2#. If the spring is stretched by # 2 m#, what is the net force on the object?

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Answer 1 · 2018-06-11T20:57:38

The net force applied on the object is #64.6# newtons.

The net force acting on the object represents the sum of all the forces which act upon it; in our case, it is

#F = G-F_e#

Where #F# is the net force, #G# is the gravity force and #F_e# is the force of elasticity, also called the tensile force.

#G = mg = 7*9.8 = 68.6 " N"#

#F = kx#

Note: #k# is the spring constant and #x# is the displacement (how much the spring is getting stretched).

#F_e = 2*2=4 " N"#

Hence,

#F = 68.6 - 4 = 64.6 " N"#