Determine whether 81-49n^4 is a difference of 2 squares. If so, factor it, if not explain why.?

Question

3641 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-12T15:04:10

Please read below;

#81 - 49n^4#

Is not a difference of #2# squares because..

Difference of two squares is denoted by: #x^2 - y^2#

Hence;

#81 - 49n^4# can be simplified as #= 9^2 - 7^2n^4#

Assuming it was;

#9^2 - 7^2n^2# then it would have been difference of two squares #=(9 + 7n) (9- 7n)#