Question

How do you completely factor `x^3 + 4x^2 - 45x`?

Answer 1

`x(x-5)(x+9)`

Explanation:

take the `x` as a common factor such that:

`x(x^{2}+4x-45)`

factorize the expression inside the brackets

`x(x^{2} + 9x-5x-45)`

`x(x(x+9)-5(x+9))`
`x(x-5)(x+9)`