Question

How do you divide `(3x^2+9x+36) / (x-3)`?

Answer 1

`(3(x^2+3x+12))/(x-3)`

Explanation:

`(3x^2+9x+36)/(x-3)`
Factorise `3x^2+9x+36`
`(3(x^2+3x+12))/(x-3)`
`x^2+3x+12` cannot be factorised with rational numbers