How do we expand:#(4x^2+5x-9)(x-5)#?

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Answer 1 · 2018-06-13T11:35:42

#4x^3-15x^2-34x+45#

As per the question, we have

#(4x^2+5x-9)(x-5)#

#=(4x^2xx x)+(5x xx x)+(-9xx x)+(4x^2xx-5)+(5x xx -5)+(-9 xx -5)#

#=(4x^3)+(5x^2)+(-9x)+(-20x^2)+(-25x)+(45)#

#=4x^3+5x^2-9x-20x^2-25x+45#

#=4x^3-15x^2-34x+45#

Hence, the answer.