Question

If `f(x) = 2x^2+1` and `g(x) = 3x-2`, what is the value of `f(g(-2))`?

Answer 1

`f(g(-2))=129`

Explanation:

First we need `g(-2)`:
`g(-2)=3(-2)-2=-6-2=-8`

Now we put that value into `f(x)`:
`f(g(-2))=f(-8)=2(-8)^2+1=2(64)+1=129`