How do you solve $0.9 x + 3 > 0.6 x$ $0.9x + 3> 0.6x$ ?

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Answer 1 · 2018-06-14T05:45:11

$x > 0.1$ $x > 0.1$

As explained below:

$0.9 x + 3 > 0.6 x$ $0.9x + 3 >0.6x$

Subtract $0.6 x$ $0.6x$ both sides:

$0.9 x - 0.6 x + 3 > 0.6 x - 0.6 x$ $0.9x-0.6x + 3 > 0.6x-0.6x$

$0.3 x + 3 > 0$ $0.3x + 3 > 0$

Subtract $3$ $3$ both sides:

$0.3 x + 0.3 - 0.3 > 0 - 0.3$ $0.3x + 0.3 -0.3 > 0-0.3$

$0.3 x > - 0.3$ $0.3x > -0.3$

Divide by $0.3$ $0.3$ both sides:

$\frac{0.3 x}{0.3} > - \frac{0.3}{3}$ $(0.3x)/0.3 > -0.3/3$

$x > 0.1$ $x > 0.1$

Always check you answer:
take $x = 0.2$ $x = 0.2$

$0.9 x + 3 > 0.6 x$ $0.9x + 3 >0.6x$

$0.9 (0.2) + 3 > 0.6 (0.2)$ $0.9(0.2) + 3 > 0.6(0.2)$

$0.18 + 3 > 0.12$ $0.18 + 3 > 0.12$

$3.18 > 0.12$ $3.18 > 0.12$ ----> That's right!

How do you solve 0.9x+3>0.6x0.9x + 3> 0.6x?