Question

How do you solve `3k = \frac { 12} { 7} + 6`?

Answer 1

`k=18/7`

Explanation:

`"sum the terms on the right side"`

`3k=12/7+42/7=54/7`

`"divide both sides by 3"`

`k=54/7-:3`

`color(white)(k)=cancel(54)^(18)/7xx1/cancel(3)^1=18/7`

Answer 2

`k=18/7`

Explanation:

We can start by getting rid of the `7` in the denominator by multiplying every term by `7`. Doing this, we now have

`7(3k)=cancel(7)(12/cancel7)+7(6)`

Notice the `7` in the denominator is cancelled out. This was the intention. We now have:

`21k=12+42`

Which simplifies to

`21k=54`

Lastly, isolating `k`, we can divide both sides by `21` to get

`k=54/21`

Both terms have a `3` in common, so we can divide the top and bottom by `3`. We get

`k=18/7`

Hope this helps!

Answer 3

Add the constants together, then divide by `k`'s coefficient. you will find that `k=18/7`

Explanation:

First, add the constants together:

`3k=12/7+6xx7/7`

`3k=12/7+42/7`

`3k=54/7`

Now, divide by `k`'s coefficient (3):

`(cancel(3)k)/color(red)(cancel(3))=54/(7xxcolor(red)(3))`

`k=(18xxcancel(3))/(7xxcolor(red)(cancel(3)))`

`color(green)(k=18/7`