Question

How do you solve for `y` in `12x-2(y-1)=10`?

Answer 1

`color(green)(y = 6x - 4 " or " 2 (3x-2)`#

Explanation:

`"To solve for 'y' in" 12x - 2(y-1) = 10`

`12x -2y + 2 = 10, " removing the bracket"`

`12x - 2y = 10 - 2 = 8, bringing constant terms together"`

`12x - 8 = 2y`

`color(green)(y) = (12x-8) / 2 = color(green)(6x - 4)`