How do you solve #2a + 10\leq 2( - 2a + 3) + 6a#?

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Answer 1 · 2018-06-15T02:39:11

No solutions

Let's start on the right side by distributing the #2#. This gives us

#2a+10<=-4a+6+6a#

Simplifying the right side terms, we get

#2a+10<=2a+6#

Since the coefficients on the #a# terms are the same, they cancel, and we're left with

#10<=6#

Which is obviously not true, so we say that this inequality has no solutions.

Hope this helps!