Question

How do you solve `1/3x+3/10=13/90`?

Answer 1

My first step would be to multiply everything by `90` to get rid of the fractions.

Explanation:

`->90/3x+(9cancel0*3)/(1cancel0)=(cancel90*13)/cancel90->30x+27=13`

Subtract `27` from both sides:
`->30x+cancel27-cancel27=13-27->30x=-14`

Now divide by `30`:
`->x=-14/30=-7/15`