What is the value of A, B, C and D?

7=A+C
-1=B+D
17=A+3C
-3=B+3D

3 Answers
Jun 15, 2018

#color(red)(=>"A"=2; "B"=0; "C"=5 and "D"=-1#

Explanation:

The 4 equations we have are:-

1st equation: #color(blue)(7="A"+"C"#

2nd equation: #color(darkorange)(-1="B"+"D"#

3rd equation:#color(green)(17="A"+3"C"#

4th equation: #color(magenta)(-3="B"+3"D"#

Taking the first and third equations first and solving for A and C

#color(blue)(=>7="A"+"C"#...… 1st eqn

#=>"A"=7-"C"#

#color(green)(=>17="A" +3"C"#..... 3rd eqn

#=>17=7-"C"+3"C"#

#=>17-7=2"C"#

#=> 10=2"C"#

#color(red)("C"=5 and "A" = 7-"C"=2#

Taking the 2nd and 4th equations first and solving for A and C.

#color(darkorange)(=>-1="B"+"D"#.... 2nd eqn

#=> "B"=-1-"D"#

#color(magenta)(=>-3="B"+3"D"#...4th eqn

#=>-3=-1-"D"+3"D"#

#=>-3+1=-"D"+3"D"#

#=>-2=2"D"#

#color(red)(=>"D"=-1 and "B"=-1-"D"=0#

~Hope this helps! :)

Jun 15, 2018

#A=2,B=0,C=5,D=-1#

Explanation:

Multiplying the first equation by #-1# and adding to the third we get

#2C=10# so #C=5#
From here we get #A=2#

Multiplying the second by #-1# and adding to the last one
#D=-1#
so
#B=0#

Jun 15, 2018

#A=2#, #B=0#, #C=5# and #D=-1#

Explanation:

As #7=A+C# and #17=A+3C#, subtracting former from latter we get

#10=2C# or #C=10/2=5#

and as #A+C=7#, #A=7-5=2#

Similarly as #-1=B+D# and #-3=B+3D#, subtracting former from latter we get

#-3-(-1)=2D# or #2D=-3+1=-2# and #D=-1#

And as #B+D=-1#, #B=-1-(-1)=-1+1=0#