How to compare these equation to #y = mx+c# ?

#y=Ax^b#

1 Answer
Jun 15, 2018

I am not sure about this but I try....

Explanation:

We can take the log of both sides to get:

#log(y)=log(Ax^b)#

use some properties to write:

#log(y)=log(A)+blog(x)#

or (the same):

#log(y)=blog(x)+log(A)#

that is a way to write #y=mx+c# involving logs....