Find The Derivative Of cot x/2 in point x=π ?

Question

find derivative of #Cotx/2# in Point #x=π#

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Answer 1 · 2018-06-16T07:00:41

#-oo#.

We have,

#f(x) = 1/2cot(x)#.

So, #d/dxf(x) = d/dx(1/2cot(x))#

#= 1/2d/dx(cot(x))# [Constant's doesn't change in differentiation]

#= -1/2csc^2(x)# [As #d/dx(cot(x)) = -csc^2(x)#]

So,

The Derivative at #x = pi# :-

#f'(pi) = -1/2csc^2(pi) = -oo# [As, #csc pi = oo#]

Hope this helps.