Question

Write the equation of a circle in standard form whose center is at (3,-2) and has a radius of 11?

Answer 1

`(x-3)^2+(y+2)^2=121`

Explanation:

Formula for a circle:

`(x-h)^2+(y-k)^2=r^2` where `(h,k)` is the center.

`(x-3)^2+(y+2)^2=121`

graph{(x-3)^2+(y+2)^2=121 [-18.16, 21.84, -10.32, 9.68]}