Question

How do you find the domain and range of `f(x) = (x)/(sqrt{x - 4})`?

Answer 1

`x>4` and #y>=4

Explanation:

Since we have a square root in the denominator we get

`x>4`

for

`x/sqrt(x-4)`we get

`x/sqrt(x-4)>=4`
this is true, since we get

`(x-4)^2>=0`