How do you solve #3x+y=0# and #5x+y=4#?
3 Answers
Explanation:
You can solve the first equation for
So, let's do it in the second: instead of
We can sum the terms in the left hand side to get
And finally solve for
Now that we know that
Explanation:
#3x+y=0to(1)#
#5x+y=4to(2)#
#"from equation "(1)color(white)(x)y=-3xto(3)#
#"substitute "y=-3x" into equation "(2)#
#5x-3x=4rArr2x=4rArrx=2#
#"substitute "x=2" into equation "(3)#
#y=-3xx2=-6#
#"point of intersection "=(2,-6)#
graph{(y+3x)(y+5x-4)=0 [-16.02, 16.02, -8, 8.02]}
Explanation:
Let ,
From
Subst .
From
Hence,