Can you please find ''x'' ?

Question

#2^x=30#

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Answer 1 · 2018-06-18T09:41:56

#x = 4.91#

We have this equation

#2^x = 30#

We add #log# to both sides

#log2^x = log 30#

Using one of the rules of logarithms, we move the #x# in front

#xlog2 = log 30#

Divide both sides by #log 2#

#x = log30/log2#

Calculate the final answer

#x = 4.91#