Question

How do you find two unit vectors parallel to vector a= [-4, -1, -6]?

Answer 1

`(4/sqrt53,1/sqrt53,6/sqrt53)` and `(-4/sqrt53,-1/sqrt53,-6/sqrt53)`

Explanation:

Consider the vector defined by `+-veca/||veca||`, where, `||veca||` is the

magnitude of `veca!=vec0`.

Here, `||veca||=sqrt{(-4)^2+(-1)^2+(-6)^2}=sqrt53`.

So, `(4/sqrt53,1/sqrt53,6/sqrt53)` and `(-4/sqrt53,-1/sqrt53,-6/sqrt53)`

are the desired vectors.