How do you factor the expression x^2 - 64x264?

2 Answers
Jun 19, 2018

See a solution process below:

Explanation:

This is a special form of the quadratic function:

color(red)(a)^2 - color(blue)(b)^2 = (color(red)(a) + color(blue)(b))(color(red)(a) - color(blue)(b))a2b2=(a+b)(ab)

Let color(red)(a)^2 = x^2a2=x2 then sqrt(color(red)(a)^2) = sqrt(x^2) -> color(red)(a) = xa2=x2a=x

Let color(blue)(b)^2 = 64b2=64 then sqrt(color(blue)(b)^2) = sqrt(64) -> color(blue)(b) = 8b2=64b=8

Substituting gives:

color(red)(x)^2 - color(blue)(64) = (color(red)(x) + color(blue)(8))(color(red)(x) - color(blue)(8))x264=(x+8)(x8)

Jun 19, 2018

(x-8)(x+8)(x8)(x+8)

Explanation:

Given: x^2-64x264.

Notice how 64=8^264=82.

=x^2-8^2=x282

Use the difference of squares property, which states that a^2-b^2=(a-b)(a+b)a2b2=(ab)(a+b). Letting x=a,b=8x=a,b=8, we get:

=(x-8)(x+8)=(x8)(x+8)