How do you simplify #(2 -sqrt 5) /(3 +sqrt5)#?
2 Answers
Jun 20, 2018
Explanation:
Jun 20, 2018
Explanation:
#"multiply the numerator/denominator by the "color(blue)"conjugate"#
#"of the denominator"#
#"the conjugate of "3+sqrt5" is "3color(red)(-)sqrt5#
#=((2-sqrt5)(3-sqrt5))/((3+sqrt5)(3-sqrt5))#
#"expand factors on numerator/denominator"#
#=(6-5sqrt5+5)/(9-5)#
#=(11-5sqrt5)/4=11/4-(5sqrt5)/4#