Find the energy of photons which corresponds to light of frequency 3*10 power12 hz?

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Answer 1 · 2018-06-20T14:28:46

Approximately #2*10^-21# joules.

The energy of a photon is given by the equation:

#E=hf#

where:

#E# is the energy in joules

#h# is Planck's constant, which is #6.63*10^-34 \ "J s"#.

#f# is the frequency in hertz

So, we get:

#E=6.63*10^-34 \ "J s"*3*10^12 \ "Hz"#

Because #1 \ "Hz"-=1 \ "s"^-1#, we get:

#=6.63*10^-34 \ "J"color(red)cancelcolor(black)"s"*3*10^12color(red)cancelcolor(black)"s"^-1#

#~~1.99*10^-21 \ "J"#