A fuse wire can with stand 0.1A of current. How many bulbs of power rating 110W/220V can be connected in series with the fuse wire, If input supply is 220V?

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Answer 1 · 2018-06-20T14:33:16

I get five bulbs...

Well, power in this case is given by the equation:

#P=IV#

where:

#P# is the power in watts

#I# is the current in amperes

#V# is the voltage in volts

So, the power of one bulb will be:

#P=0.1 \ "A"*220 \ "V"#

#=22 \ "W"#

So, the maximum number of bulbs that can be connected will be:

#b_"max"=P_"max"/P_b \ (b-="bulb")#

#=(110color(red)cancelcolor(black)"W")/(22color(red)cancelcolor(black)"W")#

#=5#