How do you solve #\frac { 49} { 15x } = \frac { 11} { 3x } - \frac { 2} { 15}#?

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Answer 1 · 2018-06-20T14:58:39

#x=3#

Multiply the entire equation by the common denominator #15x#

#\frac { 49} { 15x } = \frac { 11} { 3x } - \frac { 2} { 15}#

#15x[\frac { 49} { 15x } = \frac { 11} { 3x } - \frac { 2} { 15}]#

#49 = 5*11-2*x#

#49 = 55-2x#

#-6= -2x#

#x=3#

Answer 2 · 2018-06-20T15:02:00

Add #2/15#

#49/[15x]+2/15=11/[3x]#

Subtract #49/[15x]#

#2/15=11/[3x]-49/[15x]#

#2/15=55/[15x]-49/[15x]#

#2/15=6/[15x]#

Cross multiply

#15x xx 2 = 16 xx 6#

#30x=96#

divide by 30

#x=96/30=32/10=3.2#