How do you find the standard form of an equation with a given Vertex: (0,0) and Point on Parabola: (3,6)?
1 Answer
Jun 20, 2018
Explanation:
#"since the vertex is at the origin then the standard form is"#
#•color(white)(x)y=ax^2#
#"to find a substitute "(3,6)" into the equation"#
#6=9arArra=6/9=2/3#
#"required equation is "y=2/3x^2#
graph{(y-2/3x^2)((x-3)^2+(y-6)^2-0.04)=0 [-15.8, 15.81, -7.9, 7.9]}
