How do you simplify #(15 sqrt (8x ^16))/( 5 sqrt (2x ^4))#?

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Answer 1 · 2018-06-21T07:17:10

divide by 5

#[3sqrt(8x^16)]/[sqrt(2x^4)]#

square root the two #x# terms

#[3x^8sqrt(8)]/[x^2sqrt(2)]#

cancel the #x^2#

#[3x^6sqrt(8)]/[sqrt(2)]#

#sqrt8=sqrt4xxsqrt2=2sqrt2#

so #[3x^6sqrt(8)]/[sqrt(2)]# = #[3x^(6)2sqrt(2)]/[sqrt(2)] =[6x^6sqrt(2)]/[sqrt(2)]#

cancel the #sqrt2#

#6x^6#