How do you solve #ln(7-p)=ln(-5p-1)#?

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Answer 1 · 2018-06-21T09:28:07

#p = -2#

#ln(7-p) = ln(-5p-1)#

#7 - p = -5p - 1, "Equality Rule"##

4p = -8 " or " p = -2#

Answer 2 · 2018-06-21T09:41:45

#p=-2#

#"using the "color(blue)"law of logarithms"#

#•color(white)(x)log_b x=log_byhArrx=y#

#7-p=-5p-1#

#4p=-8rArrp=-2#