How do you solve 2sin2xcos2x?

1 Answer
Jun 21, 2018

2sin 2x.cos 2x = sin 4x.
To solve for x, it needs to have an equation.
For example, solve:
2sin 2x.cos 2x = 0
sin 4x = 0
Unit circle gives -->
4x = 0 + 2kpi --> x = (kpi)/2
4x = pi + 2kpi = (2k + 1)pi --> x = (2k + 1)pi/4
4x = (2pi) + 2kpi = (k + 1)2pi --> x = (k + 1)pi/2