Question

How can you write -2=log9 1/81 in exponential form?

write in exponential form

Answer 1

`9^-2=1/81`

Explanation:

The logarithm is defined as follows:
`log_b(a)=c` if and only if `a=b^c`.
Substituting `a=1/81`, `b=9`, and `c=-2`, we end up with this:
`log_9(1/81)=-2` if and only if `1/81=9^-2`.