How do you simplify #8 (x +2) - 4x + 7#?

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Answer 1 · 2018-06-21T21:19:01

#8(x+2)-4x+7#
#=8x+16-4x+7#
#=4x+23#

Answer 2 · 2018-06-21T21:24:18

#4x+23#

Given: #8(x+2)=4x+7#

Consider just the part #8(x+2)#

This is the same as #(x+2)+(x+2)+(x+2)+...+(x+2)#

You have 8 lots of #(x+2)# so basically you multiply everything inside the brackets by 8 giving: #8x+16#

Putting it all together:

#8x+16-4x+7#

Collecting like terms

#ubrace(8x-4x)+ubrace(16+7)#

#color(white)("dd")4xcolor(white)("dd")+color(white)("dd")23#