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How do you divide $(n^{3} - 5 n^{2} - 33 n - 37) \div (n - 9)$ $(n^3-5n^2-33n-37)div(n-9)$ using synthetic division?

1 Answer

Jun 22, 2018

$n^{3} - 5 n^{2} - 33 n - 3 = (n - 9) (2 n^{2} + 13 x n + 144) + 1259$ $n^3-5n^2-33n-3=(n-9)(2n^2+13xn+144)+1259$

Explanation:

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