How do you simplify and divide #(a^3b^2-a^2b+2a)(-ab)^-1#?

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Answer 1 · 2018-06-22T06:14:45

#-(a^2b^2-ab+2)/b#

Given -

#(a^3b^2-a^2b+2a)(-ab)^(-1)#

#(a^3b^2-a^2b+2a)/(-ab)#

#(a(a^2b^2-ab+2))/(-ab)#

#-(a^2b^2-ab+2)/b#

Answer 2 · 2018-06-22T06:16:19

#-a^2b+a-2/b#

#(a^3b^2-a^2b+2a)/(-ab)=-(a^2b)/(ab)+(a^2b)/(ab)-(2*a)/(ab)=#
#-a^2b+a-2/b#