How do you graph the function #y=-x+6#?
2 Answers
See a solution process below:
Explanation:
First, solve for two points which solve the equation and plot these points:
First Point: For
Second Point: For
We can next plot the two points on the coordinate plane:
graph{((x-6)^2+y^2-0.035)((x-4)^2+(y-2)^2-0.035)=0 [-10, 10, -5, 5]}
Now, we can draw a straight line through the two points to graph the line:
graph{(y+x-6)((x-6)^2+y^2-0.035)((x-4)^2+(y-2)^2-0.035)=0 [-10, 10, -5, 5]}
Explanation:
#"one way is to find the intercepts, that is where the graph"#
#"crosses the x and y axes"#
#• " let x = 0, in the equation for y-intercept"#
#• " let y = 0, in the equation for x-intercept"#
#x=0rArry=6larrcolor(red)"y-intercept"#
#y=0rArr-x+6=0rArrx=6larrcolor(red)"x-intercept"#
#"plot the points "(0,6)" and "(6,0)#
#"draw a straight line through them for graph"#
graph{(y+x-6)((x-0)^2+(y-6)^2-0.04)((x-6)^2+(y-0)^2-0.04)=0 [-15.79, 15.81, -7.9, 7.9]}