How do you factor: $y= s^2-8s+7$ ?

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Answer 1 · 2018-06-22T15:01:55

$y=s^2-8x+7hArrcolor(blue)(y=(s-7)(s-1))$

Since $(s+a)(s+b)=s^2+(a+b)s+ab$
we are looking for constants $a$ and $b$
such that $a xx b=+7$
and $(a+b)=-8$

Answer 2 · 2018-06-22T15:02:35

The same processes as when you use $x$

$y=(s-1)(s-8)$

Note that $1xx7=7 and 1+7=8$

but we need negative 8 so we use

$(-1)xx(-7)=+7 and (-1)+(-7)=-8$ as required

Thus $y=(s-1)(s-8)$

How do you factor: y= s^2-8s+7 y= s^2-8s+7 ?