How do you multiply $(x ^ { 2} y ^ { 4} ) ^ { 3} \cdot 2x ^ { 3} y ^ { 5}$ ?

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Answer 1 · 2018-06-22T15:03:54

We will use two exponent rules to solve this one: $(a^b)^x=a^(b*x)$ and $a^b*a^c=a^(b+c)$ .

Let's use the first rule to simplify the first half of the equation:

$(x^2y^4)^3 = x^(2*3)y^(4*3)=x^6y^12$

We now have $x^6y^12*2x^3y^5$ . Let's now use the second rule:

$2x^(6+3)y^(12+5) = 2x^9y^17$

How do you multiply (x ^ { 2} y ^ { 4} ) ^ { 3} \cdot 2x ^ { 3} y ^ { 5}(x ^ { 2} y ^ { 4} ) ^ { 3} \cdot 2x ^ { 3} y ^ { 5}?