Question

How do you evaluate the function with the given values of `x: color(white)("d")f(x)=(1/2)[x+1] ;color(white)("ddd") x=0; x=-1`?

Answer 1

`f(0)->y=1/2`
`f(-1)->y=0`

Explanation:

Suppose `x=0` then wherever there is an `x` write 0

`f(x)=1/2(x+1) color(white)("ddd")-> color(white)("ddd")f(0)=1/2(0+1)=1/2`

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Suppose `x=-1` then wherever there is an `x` write -1

`f(x)=1/2(x+1) color(white)("ddd")-> color(white)("ddd")f(0)=1/2[color(white)(2/2)(-1)+1color(white)("d")]=0`