Question

How do you write the standard form of the equation of the circle with center (0,0) R=6?

Answer 1

`x^2+y^2=36`

Explanation:

If you know the coordinates of the center `(x_0, y_0)` and the radius `r` of a circle, the equation is

`(x-x_0)^2 + (y-y_0)^2 = r^2`

In your case, the center is `(x_0, y_0) = (0,0)` and the radius is `r=6`. So, the equation is

`(x-0)^2 + (y-0)^2 = 6^2`

which you can rewrite as

`x^2+y^2=36`