How do I solve cot^2 theta +sqrt3 cot theta = 0?

1 Answer
Jun 23, 2018

theta=pmpi/2+2kpi,theta_1=-pi/6+2kpi,theta_2=5pi/6+2kpi

Explanation:

Rewriting your equation in the form
cot(theta)(cot(theta)+sqrt(3))=0
so we get two cases:

cot(theta)=0
since

cot(x)=cos(x)/sin(x)=0if cos(x)=0

we get

theta=pmpi/2+2kpi
the other case:
cot(theta)=-sqrt(3)
theta_1=-pi/6+2kpi
theta_2=(5pi)/6+2kpi