How do you divide #(2x^2+8x+16) / (x-4) #?
1 Answer
Jun 23, 2018
Explanation:
#"one way is to use the divisor as a factor in the numerator"#
#"consider the numerator"#
#color(red)(2x)(x-4)color(magenta)(+8x)+8x+16#
#=color(red)(2x)(x-4)color(red)(+16)(x-4)color(magenta)(+64)+16#
#=color(red)(2x)(x-4)color(red)(+16)(x-4)+80#
#"quotient "=color(red)(2x+16)," remainder "=80#
#(2x^2+8x+16)/(x-4)=2x+16+80/(x-4)#
