How do you find the critical points to graph $y = 2 sin (- 2 x + π) + 1$ $y= 2 sin (-2x+pi) +1$ ?

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How do you find the critical points to graph $y = 2 sin (- 2 x + π) + 1$ $y= 2 sin (-2x+pi) +1$ ?

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Answer 1 · 2018-06-24T09:55:14

As below

Explanation:

Standard form of sine function is $y = A sin (B x - C) + D$ $y = A sin (Bx - C) + D$

Given $y = 2 sin (- 2 x + π) + 1$ $y = 2 sin(-2x + pi) + 1$

$A = 2, B = - 2, C = - π, D = 1$ $A = 2, B = -2, C = -pi, D = 1$

$A m p l i t u d e = | A | = 2$ $Amplitude = |A| = 2$

$Period = \frac{2 π}{| B |} = \frac{2 π}{2} = π$ $"Period " = (2pi) / |B| = (2pi) / 2 = pi$

$Phase Shift = - \frac{C}{B} = - \frac{π}{- 2} = \frac{π}{2}, \frac{π}{2} to the RIGHT$ $"Phase Shift " = -C / B = -pi / -2 = pi/2, " " pi/2 " to the RIGHT"$

$Vertical Shift = D = 1$ $"Vertical Shift " = D = 1$

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How do you find the critical points to graph $y = 2 sin (- 2 x + π) + 1$ $y= 2 sin (-2x+pi) +1$ ?

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How do you find the critical points to graph y= 2 sin (-2x+pi) +1y=2sin(−2x+π)+1y= 2 sin (-2x+pi) +1?

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How do you find the critical points to graph $y = 2 sin (- 2 x + π) + 1$ $y= 2 sin (-2x+pi) +1$ ?