Question

How do you solve `2b ^ { 2} - 20b - 5= 0`?

Answer 1

Using quadratic formula to find roots of given quadratic equation: `2b^2-20b-5=0` as follows

`b=\frac{-(-20)\pm\sqrt{(-20)^2-4(2)(-5)}}{2(2)}`
`=\frac{20\pm2\sqrt{110}}{4}`
`=\frac{10\pm\sqrt{110}}{2}`