How do you find the derivative of #cos^6(2x+5)#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Harish Chandra Rajpoot Jun 24, 2018 Applying chain rule for differentiation as follows #\frac{d}{dx}\cos^6(2x+5)# #=\frac{d}{dx}(\cos(2x+5))^6# #=6(\cos(2x+5))^5\frac{d}{dx}(\cos(2x+5))# #=6\cos^5(2x+5)(-\sin(2x+5))\frac{d}{dx}(2x+5)# #=-6\sin(2x+5)\cos^5(2x+5)(2)# #=-12\sin(2x+5)\cos^5(2x+5)# Answer link Related questions What is the derivative of #y=cos(x)# ? What is the derivative of #y=tan(x)# ? How do you find the 108th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x)# from first principle? How do you find the derivative of #y=cos(x^2)# ? How do you find the derivative of #y=e^x cos(x)# ? How do you find the derivative of #y=x^cos(x)#? How do you find the second derivative of #y=cos(x^2)# ? How do you find the 50th derivative of #y=cos(x)# ? How do you find the derivative of #y=cos(x^2)# ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 2648 views around the world You can reuse this answer Creative Commons License