Question

How do you find the product of `(4tan(y)+4cot(y))^2`?

Answer 1

`16(tan^2(y)+cot^2(y)+2)`

Explanation:

We are using that

`(a+b)^2=a^2+2ab+b^2`
and
`tan(x)*cot(x)=1`
so we get

`16(tan(y)+cot(y))^2=`
`16(tan^2(y)+cot^2(y)+2)`