There's only one answer. Which one is it?

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1 Answer
Jun 25, 2018

The second selection is correct.

Explanation:

Here is how you figure it out.

For the first and second selections, we must let #x = 0#:

#p(0) + qy = s#

#y = s/q#

The first selection is incorrect but the second selection is correct.

For the third and fourth selections, we must let #y = 0#

#px + q(0) = s#

#x = s/p#

This shows that the third and fourth selections are incorrect.