How do you differentiate #g(x) = (x-7)(x^2+3)# using the product rule?
1 Answer
Jun 25, 2018
Explanation:
We have
applying product rule we get
#dg(x)/dx=(x-7)*dy/dx(x^2+3)+(x^2+3)*dy/dx(x-7)# #=>(x-7)*(2*x+0)+(x^2+3)*(1+0)#
using(
#=>3*x^2-14*x+3#